/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1==null) return l2;
if (l2==null) return l1;
ListNode p = new ListNode(0);
p.next = l1;
l1 = p;
ListNode q = l2;
while (q!=null) {
if (p.next!=null) {
if (q.val<p.next.val) {
ListNode temp;
temp = p.next;
p.next = q;
q = q.next;
p.next.next = temp;
} else p = p.next;
} else {
p.next = q;
return l1.next;
}
}
return l1.next;
}
}
1. dummy node.
回复删除2. two pointers.