/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; left = null; right = null; }
* }
*/
public class Solution {
public ArrayList<TreeNode> generateTrees(int n) {
return dfs(1, n);
}
public ArrayList<TreeNode> dfs(int start, int end) {
ArrayList<TreeNode> res = new ArrayList<TreeNode> ();
if (start>end) {
res.add(null);
return res;
}
for (int i=start; i<=end; i++) {
ArrayList<TreeNode> left = dfs(start, i-1);
ArrayList<TreeNode> right = dfs(i+1, end);
for (int j=0; j<left.size(); j++) {
for (int k=0; k<right.size(); k++) {
TreeNode root = new TreeNode(i);
root.left = left.get(j);
root.right = right.get(k);
res.add(root);
}
}
}
return res;
}
}
1. DFS.
回复删除2. 对1..n中的每一个数都依次让它做root,然后分出左右区间.最后把左右区间求得的子结果依次分别作为root的左右孩子.
3. 当start>end时,用null占位.